Python Coding Challenge - Question with Answer (ID -030126)

 

Code Explanation:

List Initialization

lst = [1, 2, 3]

A list named lst is created.

It contains three elements: 1, 2, and 3.

Empty List Creation

out = []

An empty list named out is created.

This list will store the result.

For Loop Setup

for i in range(len(lst)):

len(lst) → 3

range(3) → 0, 1, 2

So the loop is ready to run with i = 0, then 1, then 2.

First Iteration of Loop

out.append(lst[i])

First value of i is 0

lst[0] is 1

So 1 is appended to out

Now out = [1]

Break Statement

break

break stops the loop immediately.

No further iterations happen (i = 1 and i = 2 are skipped).

Print Statement

print(out)

Prints the contents of out.

Final Output

[1]

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