Python Coding Challenge - Question with Answer (ID -170126)

 

Code Explanation:

1. Global Variable Definition

x = 10

A global variable x is created.

Value of x is 10.

This variable is accessible outside functions.

2. Function Definition (outer)

def outer():

A function named outer is defined.

No code runs at this point.

Function execution starts only when called.

3. Local Variable Inside Function

    x = 5

A local variable x is created inside outer.

This shadows the global x.

This x exists only within outer().

4. Lambda Function and Closure

    return map(lambda y: y + x, range(3))

range(3) produces values: 0, 1, 2

The lambda function:

Uses variable x

Captures x from outer’s local scope

This behavior is called a closure

map() is lazy, so no calculation happens yet.

A map object is returned.

5. Global Variable Reassignment

x = 20

The global x is updated from 10 to 20.

This does not affect the lambda inside outer.

Closures remember their own scope, not global changes.

6. Function Call and Map Evaluation

result = list(outer())

outer() is called.

Inside outer():

x = 5 is used

list() forces map() execution:

y Calculation Result

0 0 + 5 5

1 1 + 5 6

2 2 + 5 7

Final list becomes:

[5, 6, 7]

7. Output

print(result)

Output:

[5, 6, 7]

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