The given code creates a set s using a set comprehension to check if each element in the list lst is even (True) or not (False). The condition n % 2 == 0 is used to determine if an element is even. Here's the code and its output:
Output:
{False, True}
In this case, the set s contains both True and False because there are even and odd numbers in the list. The set comprehension creates a set of unique values based on the condition specified.
Using comprehension how will you convert
{'a' : 1, 'b' : 2, 'c' : 3, 'd' : 4, 'e' : 5}
into
{'A' : 100, 'B' : 200, 'C' : 300, 'D' : 400, 'E' : 500}?
d = {'a' : 1, 'b' : 2, 'c' : 3, 'd' : 4, 'e' : 5}
d = {key.upper( ) : value * 100 for (key, value) in d.items( )}
print(d)
original_dict = {'a': 1, 'b': 2, 'c': 3, 'd': 4, 'e': 5}
converted_dict = {key.upper(): value * 100 for key, value in original_dict.items()}
print(converted_dict)
Code:
print(max(min(False, False), 1, True))
1
Explanation:
The min function returns the smallest value among its arguments. Since False is considered 0 in Python, the min of False and False is still False. Then, the max function returns the largest value among False, 1, and True. Since True is equivalent to 1 in Python and 1 is greater than 0, the max function returns 1.
print(min(max(False,-3,-4), 2,7))
Let's break down the expression step by step:
max(False, -3, -4): This evaluates to False because False is treated as 0 in numerical comparisons, and 0 is not greater than -3 or -4.
min(False, 2, 7): This evaluates to False because False is treated as 0 in numerical comparisons, and 0 is the minimum among False, 2, and 7.
So, the output of the expression will be False.
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my_tuple = (5, 12, 19, 3, 25)
tup = my_tuple[-2::-2]
print(tup)
Sure! The output of the code is:
(3, 12)
Explanation:
You created a tuple named my_tuple with five elements: 5, 12, 19, 3, and 25.
Then, you created another tuple named tup by slicing my_tuple from the second-last element (-2) to the first element (-1) with a step size of -2 (meaning you iterate from the second-last element to the first element, reversing the order every two elements).
Finally, you printed the tup tuple, which contains the elements extracted from my_tuple: (3, 12).
%20Professional%20Certificate.PNG)
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Run experiments and train models
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What Industry 4.0 is and what factors have enabled the IIoT.
Key skills to develop to be employed in the IIoT space.
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a. Tuple comprehension offers a fast and compact way to generate a tuple.
Answer
True
b. List comprehension and dictionary comprehension can be nested.
Answer
True
c. A list being used in a list comprehension cannot be modified when it is
being iterated.
Answer
True
d. Sets being immutable cannot be used in comprehension.
Answer
False
e. Comprehensions can be used to create a list, set or a dictionary.
Answer
True
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def fun(a, *args, s = '!') :
print(a, s)
for i in args :
print(i, s)
fun(100)
.png)
a. Dictionary elements can be accessed using position-based index.
Answer
False
b. Dictionaries are immutable.
Answer
False
c. Insertion order is preserved by a dictionary.
Answer
False
d. The very first key - value pair in a dictionary d can be accessed using the
expression d[0].
Answer
False
e. courses.clear( ) will delete the dictionary object called courses.
Answer
False
f. It is possible to nest dictionaries.
Answer
True
g. It is possible to hold multiple values against a key in a dictionary
Answer
True
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Free Code :
from colorama import Fore
import pyfiglet
font = pyfiglet.figlet_format('Merry Christmas ')
print(Fore.GREEN+font)
#clcoding.com
Importing Libraries:
from colorama import Fore
import pyfiglet
The colorama library is used for adding color to the output text in the console.
The pyfiglet library is used for creating ASCII art text.
Creating ASCII Art:
font = pyfiglet.figlet_format('Merry Christmas ')
The pyfiglet.figlet_format function is used to convert the text "Merry Christmas" into ASCII art format using a specific font. In this case, it uses the default font.
Printing in Green:
print(Fore.GREEN + font)
Fore.GREEN sets the text color to green using Colorama.
font contains the ASCII art text generated by PyFiglet.
The print statement then outputs the combined result, which is the ASCII art text in green.
To run this code, you'll need to have the colorama and pyfiglet libraries installed. You can install them using the following commands:
pip install colorama
pip install pyfiglet
After installing the required libraries, you can run the script to see the "Merry Christmas" message in green ASCII art in your terminal.
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The discard() method in Python is used to remove a specified element from a set. If the element is not present in the set, discard() does nothing and does not raise an error.
In the code
s = {1, 3, 7, 6, 5}
s.discard(4)
print(s)
The element 4 is not present in the set s, so the discard() method will do nothing. The output will be the original set:
{1, 3, 5, 6, 7}
The set s remains unchanged because the attempt to discard the non-existent element 4 has no effect.
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num1 = num2 = (10, 20, 30, 40, 50)
print(isinstance(num1, tuple))
The above code creates a tuple (10, 20, 30, 40, 50) and assigns it to both num1 and num2. Then, it checks if num1 is an instance of the tuple class using the isinstance() function and prints the result.
The correct output of the code will be:
True
This is because both num1 and num2 refer to the same tuple object, and since that object is indeed a tuple, the isinstance() function returns True.
num1 = num2 = (10, 20, 30, 40, 50)
print(num1 is num2)
The above code checks if num1 and num2 refer to the same object in memory using the is keyword. Since both num1 and num2 are assigned the same tuple (10, 20, 30, 40, 50), which is an immutable object, the result will be True. Here's the correct output:
True
This is because both variables (num1 and num2) point to the same memory location where the tuple is stored.
num1 = num2 = (10, 20, 30, 40, 50)
print(num1 is not num2)
The code checks if num1 and num2 do not refer to the same object in memory using the is not comparison. Since both num1 and num2 are assigned the same tuple (10, 20, 30, 40, 50), the result will be False. Here's the correct output:
False
This is because both variables (num1 and num2) point to the same memory location where the tuple is stored, so the is not comparison returns False.
num1 = num2 = (10, 20, 30, 40, 50)
print(20 in num1)
The code checks if the value 20 is present in the tuple assigned to the variable num1. Since 20 is one of the values in the tuple (10, 20, 30, 40, 50), the result will be True. Here's the correct output:
True
The in keyword is used to check membership, and it returns True if the specified value is found in the sequence (in this case, the tuple num1).
num1 = num2 = (10, 20, 30, 40, 50)
print(30 not in num2)
The code checks if the value 30 is not present in the tuple assigned to the variable num2. Since 30 is one of the values in the tuple (10, 20, 30, 40, 50), the result will be False. Here's the correct output:
False
The not in keyword is used to check if a value is not present in a sequence. In this case, 30 is present in the tuple num2, so the expression evaluates to False.
In the code snippet you provided, you have defined two different sets, s and t, and then printed their types. Let me explain the code step by step:
s = {}
Here, you have defined an empty set. However, the syntax you used ({}) actually creates an empty dictionary in Python, not an empty set. To create an empty set, you should use the set() constructor like this:
s = set()
Now, let's move to the second part of the code:
t = {1, 4, 5, 2, 3}
Here, you have defined a set t with the elements 1, 4, 5, 2, and 3.
Finally, you printed the types of s and t:
print(type(s), type(t))
This will output the types of s and t. If you correct the creation of the empty set as mentioned above, the output will be:
<class 'set'> <class 'set'>
This indicates that both s and t are of type set
.png)
Code :
from colorama import Fore
def heart_shape(msg="Merry Christmas"):
lines = []
for y in range(15, -15, -1):
line = ""
for x in range(-30, 30):
f = ((x * 0.05) ** 2 + (y * 0.1) ** 2 - 1) ** 3 - (x * 0.05) ** 2 * (y * 0.1) ** 3
line += msg[(x - y) % len(msg)] if f <= 0 else " "
lines.append(line)
print(Fore.RED+"\n".join(lines))
print(Fore.GREEN+msg)
heart_shape() # Call the function to create the heart
#clcoding.com
.png)
a. Python is free to use and distribute.
Answer
True
b. Same Python program can work on different OS - microprocessor combinations.
Answer
True
c. It is possible to use C++ or Java libraries in a Python program.
Answer
True
d. In Python type of the variable is decided based on its usage.
Answer
True
e. Python cannot be used for building GUI applications.
Answer
False
f. Python supports functional, procedural, object-oriented and eventdriven programming models.
Answer
True
g. GUI applications are based on event-driven programming model.
Answer
True
h. Functional programming model consists of interaction of multiple objects.
Answer
False
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