Python Coding Challenge - Question with Answer (ID -010126)

 Explanation:

Create a list

nums = [1, 2, 3]

A list named nums is created with three elements: 1, 2, and 3.

Apply map()

result = map(lambda x: x * 2, nums)

map() creates an iterator that will apply lambda x: x * 2 to each element of nums.

Important: At this point, no calculation happens yet — map() is lazy.

Clear the original list

nums.clear()

This removes all elements from nums.

Now nums becomes an empty list: [].

Convert map to list and print

print(list(result))

Now iteration happens.

But nums is already empty.

So map() has no elements to process.

Final Output

[]

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