Python Coding challenge - Day 965| What is the output of the following Python Code?

 

Code Explanation:

1. Defining the Base Class

class Step:

A class named Step is defined.

2. Making the Class Callable

    def __call__(self, x):

        return x + 1

__call__ makes instances of Step callable like functions.

When an object is called (obj(x)), this method runs.

It returns x + 1.

3. Defining a Subclass

class Pipe(Step):

Pipe inherits from Step.

It inherits all behavior unless overridden.

4. Overriding __call__ in the Subclass

    def __call__(self, x):

        return super().__call__(x) * 2

Pipe overrides the __call__ method.

super().__call__(x) calls Step.__call__(x) → returns x + 1.

That result is multiplied by 2.

So Pipe()(x) returns (x + 1) * 2.

5. Creating and Calling the Object

print(Pipe()(3))

Step-by-step:

Pipe() creates an instance of Pipe.

Pipe()(3) calls its __call__ method with x = 3.

super().__call__(3) → 3 + 1 = 4.

4 * 2 = 8.

print outputs 8.

6. Final Output

8

Final Answer

✔ Output:

8

100 Python Programs for Beginner with explanation