Python Coding challenge - Day 948| What is the output of the following Python Code?

 

Code Explanation:

1. Defining the Descriptor Class

class D:

A class named D is defined.

It will be used as a descriptor.

2. Implementing the __get__ Method

    def __get__(self, obj, owner):

        return 1

__get__ makes D a non-data descriptor (because it only defines __get__).

This method is called whenever the attribute is accessed.

It always returns 1.

3. Using the Descriptor in a Class

class A:

    x = D()

x is a class attribute managed by descriptor D.

Any access to x will trigger D.__get__.

4. Creating an Instance

a = A()

An object a of class A is created.

Initially:

a.__dict__ = {}

5. Assigning to a.x

a.x = 10

Since D does not implement __set__, assignment does not go through the descriptor.

Python stores the value directly in the instance dictionary:

a.__dict__["x"] = 10

6. Accessing a.x

print(a.x)

Here’s what Python does:

Looks for x on the class A and finds that it is a descriptor.

Calls:

D.__get__(D_instance, a, A)

__get__ returns 1.

The instance value a.__dict__["x"] is ignored.

7. Final Output

1

Final Answer

✔ Output:

1

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