Python Coding challenge - Day 945| What is the output of the following Python Code?

 

Code Explanation:

1. Defining a Custom Metaclass

class Meta(type):

Meta is a metaclass because it inherits from type.

A metaclass controls how classes are created.

2. Defining the __prepare__ Method

    @classmethod

    def __prepare__(cls, name, bases):

        print("prepare", name)

        return {}

__prepare__ is called before the class body is executed.

It must return a mapping (usually a dictionary) that will be used to store the class attributes.

Parameters:

cls → the metaclass (Meta)

name → name of the class being created ("A")

bases → parent classes

What it does:

Prints "prepare A"

Returns an empty dictionary {} that will be used as the class namespace.

3. Creating Class A

class A(metaclass=Meta):

    x = 1

What happens internally:

Python sees metaclass=Meta.

Calls:

Meta.__prepare__("A", ())

Prints:

prepare A

The returned {} is used to execute the class body.

x = 1 is stored inside that dictionary.

After class body execution, Meta.__new__ (inherited from type) is called to create the class.

So class A is created with attribute x = 1.

4. Final Output

prepare A

(Nothing else is printed because there is no print after that.)

Final Answer

✔ Output:

prepare A

900 Days Python Coding Challenges with Explanation