🐍 Python Pattern Challenge — Day 15

Pattern printing is a simple but powerful way to improve your Python loops, spacing, repetition, and logical thinking. For Day 15, let's create a simple Number 1 Diamond Pattern.

The pattern uses only the number 1, but the number of 1s increases toward the center and then decreases, creating a symmetric diamond.

Today's Challenge

Write a Python program to print:

Best and cleanest code will be rewarded! 🏆

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Solution 1 — Using Nested for Loops

n = 5

for i in range(1, n + 1):
    print("  " * (n - i), end="")

    for j in range(i):
        print("1", end="   ")

    print()

for i in range(n - 1, 0, -1):
    print("  " * (n - i), end="")

    for j in range(i):
        print("1", end="   ")

    print()

How it works

The first loop creates the increasing half:

         1
      1   1
    1   1   1
  1   1   1   1
1   1   1   1   1

The second loop creates the decreasing half:

    1   1   1  1
    1   1   1
      1   1
        1

This creates the complete symmetric diamond.

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Solution 2 — Using String Multiplication

n = 5

for i in range(1, n + 1):
    print("  " * (n - i) + "1   " * i)

for i in range(n - 1, 0, -1):
    print("  " * (n - i) + "1   " * i)

How it works

This line:

" " * (n - i)

controls the indentation.

And:

"1 " * i

prints the required number of 1s.

For example, when i = 3:

1 1 1

is generated automatically.

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Solution 3 — Using a Single Loop

n = 5

for i in list(range(1, n + 1)) + list(range(n - 1, 0, -1)):
    print("  " * (n - i) + "1   " * i)

How it works

Instead of using two separate loops, we create one sequence:

[1, 2, 3, 4, 5, 4, 3, 2, 1]

Each value determines how many 1s should appear on that row.

This makes the code short and easy to understand.

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Solution 4 — Using a Function

def number_one_diamond(n):

    for i in list(range(1, n + 1)) + list(range(n - 1, 0, -1)):
        print("  " * (n - i) + "1   " * i)


number_one_diamond(5)

Now you can easily change the size:

number_one_diamond(7)

and generate a larger pattern.

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⚡ Short & Clean Code

for i in [1, 2, 3, 4, 5, 4, 3, 2, 1]:
    print("  " * (5-i) + "1   " * i)

🔥 Just one loop is enough to create the complete pattern.

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🚀 Challenge Yourself

Can you modify this pattern:

• Take n from the user using input()?
• Replace 1 with *?
• Replace 1 with letters?
• Create the same pattern using a while loop?
• Create a hollow version of the diamond?
• Generate the increasing/decreasing sequence without manually writing it?

Drop your solution below! 👇

15 Days. 15 Patterns. Stronger Python Logic. 🐍🔥

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Book: Data Structures and Algorithm Design using Python