Python Coding Challenge - Question with Answer (ID 260926)

 

Explanation:

🟢 1. Assigning "10" to x

x = "10"

Here, "10" is a string, not an integer.

x → "10"

type(x) → str

🟡 2. x * 2

x * 2

Because x is a string, * 2 repeats the string.

"10" * 2

   ↓

"1010"

⚠️ It does not perform 10 × 2.

🔵 3. int(x)

int(x)

The string "10" is converted into the integer 10.

"10" → 10

🟠 4. Integer Division // 2

int(x) // 2

Becomes:

10 // 2

So:

5

🟣 5. str(...)

Now:

str(int(x) // 2)

converts the integer 5 back into a string:

5 → "5"

🔴 6. Final +

The expression is now:

"1010" + "5"

Both are strings, so + performs string concatenation:

"1010" + "5"

       ↓

"10105"

⚡ Complete Flow

x = "10"

   ↓

x * 2

   ↓

"1010"

int("10") // 2

   ↓

10 // 2

   ↓

5

   ↓

str(5)

   ↓

"5"

"1010" + "5"

   ↓

"10105"

✅ Final Output

10105

Book: Python for Cybersecurity