Code Explanation:
1️⃣ Creating the List
data = [1, 2, 2, 3, 3, 3]
The list contains repeated values:
1 → 1 time
2 → 2 times
3 → 3 times
2️⃣ Creating Unique Values with set()
set(data)
set() removes duplicates.
So:
data → [1, 2, 2, 3, 3, 3]
set(data) → {1, 2, 3}
The order of a set should not be relied upon, but that doesn't affect the final result here.
3️⃣ Dictionary Comprehension
d = {x: data.count(x) for x in set(data)}
This creates a dictionary where:
key = number
value = frequency of that number
For x = 1
data.count(1)
gives:
1
So:
1 → 1
For x = 2
data.count(2)
gives:
2
So:
2 → 2
For x = 3
data.count(3)
gives:
3
So:
3 → 3
Therefore:
d = {1: 1, 2: 2, 3: 3}
4️⃣ Finding the Most Frequent Value
x = max(d, key=d.get)
This is the trickiest line.
Normally:
max(d)
would find the largest key.
But:
max(d, key=d.get)
tells Python:
Compare the dictionary keys according to their values.
Python effectively checks:
d.get(1) → 1
d.get(2) → 2
d.get(3) → 3
The largest value is 3.
Therefore:
x = 3
5️⃣ Getting the Frequency
d[x]
Since:
x = 3
Python evaluates:
d[3]
which gives:
3
So:
d[x] → 3
6️⃣ Printing the Result
print(x, d[x])
We have:
x = 3
d[x] = 3
Therefore:
✅ Final Output
3 3

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