Tuesday, 22 September 2026

Python Coding challenge - Day 1255| What is the output of the following Python Code?

 


Code Explanation:

1️⃣ Creating the List
data = [1, 2, 2, 3, 3, 3]

The list contains repeated values:

1 → 1 time
2 → 2 times
3 → 3 times

2️⃣ Creating Unique Values with set()
set(data)

set() removes duplicates.

So:

data → [1, 2, 2, 3, 3, 3]

set(data) → {1, 2, 3}

The order of a set should not be relied upon, but that doesn't affect the final result here.

3️⃣ Dictionary Comprehension
d = {x: data.count(x) for x in set(data)}

This creates a dictionary where:

key = number
value = frequency of that number
For x = 1
data.count(1)

gives:

1

So:

1 → 1
For x = 2
data.count(2)

gives:

2

So:

2 → 2
For x = 3
data.count(3)

gives:

3

So:

3 → 3

Therefore:

d = {1: 1, 2: 2, 3: 3}

4️⃣ Finding the Most Frequent Value
x = max(d, key=d.get)

This is the trickiest line.

Normally:

max(d)

would find the largest key.

But:

max(d, key=d.get)

tells Python:

Compare the dictionary keys according to their values.

Python effectively checks:

d.get(1) → 1
d.get(2) → 2
d.get(3) → 3

The largest value is 3.

Therefore:

x = 3

5️⃣ Getting the Frequency
d[x]

Since:

x = 3

Python evaluates:

d[3]

which gives:

3

So:

d[x] → 3

6️⃣ Printing the Result
print(x, d[x])

We have:

x    = 3
d[x] = 3

Therefore:

✅ Final Output
3 3

400 Days Python Coding Challenges with Explanation

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