Python Coding Challenge - Question with Answer (ID 190926)

 

Explanation:

1. Creating an Empty List

x = []

x is an empty list.

It contains no elements.

x → []

2. Using all(x)

all(x)

all() checks whether every element in an iterable is truthy.

Here, the list is empty:

[]

There is no element that is False.

Python therefore returns:

all([]) → True

💡 This is called vacuous truth.

3. Using any(x)

any(x)

any() checks whether at least one element in an iterable is truthy.

But x contains nothing:

[]

So there isn't even a single truthy element.

Therefore:

any([]) → False

4. The print() Statement

print(all(x), any(x))

Substituting the results:

print(True, False)

⚡ Complete Flow

x = []

   ↓

all([]) → True

   ↓

any([]) → False

   ↓

Output → True False

✅ Final Output:

True False

Book: Python Functions in Depth — Writing Clean, Reusable, and Powerful Code