Python Coding Challenge - Question with Answer (ID 150926)

 

Code Explanation:

1. Assigning a Value to x

x = 4

A variable x is created.

Its value is 4.

So:

x = 4

2. Creating the Lambda Function

f = lambda x: x + 2

A small anonymous function is created and stored in f.

The function takes one argument called x.

It returns x + 2.

It is equivalent to:

def f(x):

    return x + 2

⚠️ Here, the x inside the lambda is a local parameter. It does not change the outside x.

3. Calling the Function

f(3)

3 is passed to the lambda.

Inside the function:

x = 3

Therefore:

x + 2

= 3 + 2

= 5

So:

f(3) = 5

4. Adding the Outside x

f(3) + x

We already know:

f(3) = 5

And the outside variable is still:

x = 4

Therefore:

5 + 4 = 9

5. print() Statement

print(f(3) + x)

Python prints:

9

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