Thursday, 17 September 2026

Python Coding Challenge - Question with Answer (ID 170926)

 


Code Explanation:

1. Assigning the Initial Value
x = 5
A variable x is created.
Its value is 5.
x = 5

2. Creating the Lambda Function
f = lambda n=x: n
This is the tricky part. ๐Ÿ‘€
The lambda has a parameter n.
n=x means x is used as the default value.
At this moment, x is 5.

So Python effectively stores:

n = 5

The lambda is equivalent to:

def f(n=5):
    return n

3. Changing x
x = 9

Now the outside variable becomes:

x = 9

⚠️ But this does not change the default value already stored inside the lambda.

The lambda still has:

n = 5

4. Calling the Function
f()

No argument is provided, so Python uses the stored default:

n = 5

Therefore:

f() → 5

5. Printing the Result
print(f())

The function returns 5, so the output is:

Final Output:

5

Books: Python Functions in Depth — Writing Clean, Reusable, and Powerful Code

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