Python Coding Challenge - Question with Answer (01301025)

 

Step-by-Step Execution

1. range(3) → means the loop will normally run for i = 0, 1, 2.

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2. First iteration:

   i = 0

   • print(i) → prints 0

   • if i == 1: → condition False, so it continues.

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3. Second iteration:

   i = 1

   • print(i) → prints 1

   • if i == 1: → condition True

   • Executes break → this stops the loop immediately.

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4. Because the loop is terminated using break,
   the else block is skipped.

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Output

0
1

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Key Concept

In Python,
for...else and while...else blocks work like this:

• The else part runs only if the loop completes normally (no break).

• If a break statement is used, the else block will not execute.

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Try Changing It

If you remove the break, like this:

for i in range(3):
    print(i)
else: 
    print('Finished')

Then output will be:

0
1
2
Finished

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