Python Coding Challenge - Question with Answer (01281025)

 

Explanation:

Line 1: x = 1

A global variable x is created and assigned the value 1.

So right now:

Global scope → x = 1

Line 2–5: Define the function test()

def test():

    global x

    for x in range(3):

        pass

This defines a function named test, but does not execute it yet.

Inside the function:

global x tells Python: “Use the global variable x, not a local one.”

So any change to x inside this function will affect the global x directly.

Inside the Function – The for Loop

for x in range(3):

    pass

range(3) → generates [0, 1, 2].

The loop runs three times:

Iteration 1: x = 0

Iteration 2: x = 1

Iteration 3: x = 2

The pass statement does nothing (it’s just a placeholder).

But each time, x is reassigned, and because x is global, it changes the global variable!

Line 6: test()

Now the function test() is called.

The loop executes, and when it finishes:

x = 2

because the last value from range(3) is 2.

Line 7: print(x)

Now we’re outside the function, in the global scope again.

x has been changed globally by the function to 2.

So:

Output: 2

Final Output

2

700 Days Python Coding Challenges with Explanation