Python Coding Challange - Question with Answer (01191025)

 

Explanation:

Step 1 – Initialization

a = 0

We start with the variable a equal to 0.

Step 2 – Outer Loop Starts

for i in range(3):

This loop will run 3 times.

Values of i will be: 0, 1, 2

Step 3 – Inner Loop Starts

for j in range(3):

For each i, this inner loop also runs 3 times.

Values of j will be: 0, 1, 2, but it may stop early because of break.

Step 4 – Increment a

a += 1

Every time this line runs, a increases by 1.

Step 5 – Check Condition

if a % 3 == 0:

    break

If a becomes divisible by 3, the inner loop breaks (but only the inner loop, not the outer one).

Let’s Trace the Values

Iteration i j a += 1 Condition a % 3 == 0 Inner Loop

1 0 0 a = 1 No continue

2 0 1 a = 2 No continue

3 0 2 a = 3 Yes → break stop inner

Inner loop stops, outer loop continues to next i

| 4 | 1 | 0 | a = 4 | No | continue |

| 5 | 1 | 1 | a = 5 | No | continue |

| 6 | 1 | 2 | a = 6 | Yes → break | stop inner |

Inner loop stops again, outer loop continues

| 7 | 2 | 0 | a = 7 | No | continue |

| 8 | 2 | 1 | a = 8 | No | continue |

| 9 | 2 | 2 | a = 9 | Yes → break | stop inner |

Outer loop also ends now (all 3 i loops are done)

Final Step

print(a)

Final value of a is: 9

Final Output

9

APPLICATION OF PYTHON IN FINANCE