Thursday, 13 November 2025

Python Coding challenge - Day 844| What is the output of the following Python Code?

 


Code Explanation:

1. Defining the Class
class Check:

A class named Check is created.

It will contain a method that checks if a number is even.

2. Defining the Method
def even(self, n):
    return n if n % 2 == 0 else 0

even() is an instance method that takes one argument n.

It uses a conditional expression (ternary operator):

If n % 2 == 0 → number is even → return n.

Otherwise → return 0.

In simple terms:
Even number → returns itself
Odd number → returns 0

3. Creating an Object
c = Check()

Creates an instance c of the Check class.

This object can now call the even() method.

4. Initializing a Variable
s = 0

A variable s is set to 0.

It will be used to accumulate the sum of even numbers.

5. Loop from 1 to 5
for i in range(1, 6):
    s += c.even(i)

The loop runs for i = 1, 2, 3, 4, 5.

Each time, it calls c.even(i) and adds the result to s.

Let’s trace it step-by-step:

Iteration i c.even(i) Calculation s after iteration
1 1 0 (odd) 0 + 0 0
2 2 2 (even) 0 + 2 2
3 3 0 (odd) 2 + 0 2
4 4 4 (even) 2 + 4 6
5 5 0 (odd) 6 + 0 6


6. Printing the Result
print(s)

Prints the final accumulated value of s.

After the loop, s = 6.

Final Output
6


400 Days Python Coding Challenges with Explanation

Python Coding challenge - Day 846| What is the output of the following Python Code?

 


Code Explanation:

1. Defining the Class
class Word:

Creates a class named Word.

This class can contain methods to perform operations on words or strings.

2. Defining a Method
def vowels(self, word):

Defines a method named vowels inside the Word class.

self refers to the instance of the class calling the method.

word is the string parameter for which we want to count vowels.

3. Initializing a Counter
count = 0

Initializes a variable count to 0.

This variable will keep track of the number of vowels found in the word.

4. Looping Through Each Character
for ch in word:

Iterates over each character ch in the input string word.

5. Checking if Character is a Vowel
if ch.lower() in "aeiou":
    count += 1

ch.lower() converts the character to lowercase, so the check is case-insensitive.

If the character is in "aeiou" → it is a vowel → increment count by 1.

Let’s trace for "Object":

Character ch.lower() Vowel? count after step
O                   o                   Yes        1
b                   b                    No        1
j                         j                    No        1
e                   e                    Yes        2
c                   c                    No        2
t                   t                    No        2
6. Returning the Count
return count


Returns the total number of vowels found in the word.

7. Creating an Object
w = Word()

Creates an instance w of the Word class.

This object can now call the vowels() method.

8. Calling the Method and Printing
print(w.vowels("Object"))

Calls the vowels() method on the object w with "Object" as input.

Returns 2 → number of vowels (O and e).

print() displays the result.

Final Output
2

400 Days Python Coding Challenges with Explanation

Python Coding challenge - Day 845| What is the output of the following Python Code?

Code Explanation:

1. Defining the Class
class Math:

This line defines a class called Math.

A class is a blueprint for creating objects.

All methods related to mathematical operations can go inside this class.

2. Defining the Method
def fact(self, n):

Defines a method called fact to calculate the factorial of a number n.

self refers to the instance of the class that will call this method.

3. Initializing the Result Variable
res = 1

Initializes a variable res to 1.

This variable will store the factorial as it is computed in the loop.

4. Loop to Compute Factorial
for i in range(1, n+1):
    res *= i

range(1, n+1) generates numbers from 1 to n inclusive.

On each iteration, res *= i multiplies the current value of res by i.

Let’s trace it for n = 4:

Iteration i res calculation res after iteration
1 1 1 * 1 1
2 2 1 * 2 2
3 3 2 * 3 6
4 4 6 * 4 24

5. Returning the Result
return res

After the loop, res holds the factorial of n.

return res sends this value back to the caller.

6. Creating an Object
m = Math()

Creates an instance m of the class Math.

This object can now access the fact method.

7. Calling the Method and Printing
print(m.fact(4))

Calls fact(4) on object m.

Computes 4! = 1*2*3*4 = 24.

print() outputs the result to the console.

Final Output
24

500 Days Python Coding Challenges with Explanation

 

Python Coding Challenge - Question with Answer (01141125)

 

Explanation:

1. Class Declaration
class Counter:

This line defines a class named Counter.

2. Class Variable (Shared Across All Calls)
    x = 1

This is a class variable, not tied to any object.

Its value is shared every time the method is called.

Initial value: 1

3. Method Without self
    def nxt():
        Counter.x *= 2
        return Counter.x
Explanation:
def nxt(): → This method does not use self because we are not creating objects.

Counter.x *= 2 → Every time the method is called, the value of x is doubled.

return Counter.x → The updated value is returned.

4. Loop That Calls the Method Several Times
for _ in range(4):

This loop runs 4 times.

5. Printing the Result Each Time
    print(Counter.nxt(), end=" ")

Each loop iteration calls Counter.nxt()

The returned value is printed

end=" " keeps everything on one line with spaces

Final Output
2 4 8 16

Python Interview Preparation for Students & Professionals



Python Coding challenge - Day 843| What is the output of the following Python Code?

 


Code Explanation:

1. Defining the Class
class A:

A new class named A is created.

This acts as a blueprint for creating objects (instances).

2. Declaring a Class Variable
count = 0

count is a class variable, shared by all objects of class A.

It belongs to the class itself, not to individual instances.

Initially, A.count = 0.

3. Defining the Constructor
def __init__(self):
    A.count += 1

__init__ is the constructor, called automatically every time an object of class A is created.

Each time an object is created, this line increases A.count by 1.

So it counts how many objects have been created.

4. Loop to Create Multiple Objects
for i in range(3):
    a = A()

The loop runs 3 times (i = 0, 1, 2).

Each time, a new object a of class A is created, and the constructor runs.

Let’s trace it:

Iteration Action A.count value
1st (i=0) new A() created 1
2nd (i=1) new A() created 2
3rd (i=2) new A() created 3

After the loop ends, A.count = 3.

The variable a refers to the last object created in the loop.

5. Printing the Count
print(a.count)

Here, we access count through the instance a, but since count is a class variable, Python looks it up in the class (A.count).

The value is 3.

Final Output
3

500 Days Python Coding Challenges with Explanation

10 Python One-Liners That Will Blow Your Mind

 



1 Reverse a string


text="Python"
print(text[::-1])

#source code --> clcoding.com 

Output:

nohtyP


2 Swap two vairables without a temp variable


a,b=5,20
a,b=b,a
print(a,b)

#source code --> clcoding.com 

Output:

20 5

3. check the string is palindrome


word="madam"
print(word==word[: :-1])

#source code --> clcoding.com 

Output:

True


4. Count Frequency of each element in a list


from collections import Counter
print(Counter(['a','b','c','b','a']))

#source code --> clcoding.com 

Output:

Counter({'a': 2, 'b': 2, 'c': 1})

5. Get all even numbers from a list


nums=[1,2,3,4,5,6,7,8]
print([n for n in nums if n%2==0])

#source code --> clcoding.com 

Output:

[2, 4, 6, 8]


6. Flatten a nested list


nested=[[1,2],[3,4],[5,6]]
print([x for sub in nested for x in sub])

#source code --> clcoding.com 

Output:

[1, 2, 3, 4, 5, 6]

7. Find the factorial of a number


import math
print(math.factorial(5))

#source code --> clcoding.com 
Output:
120

8. Find common elements between two list


a=[1,2,4,5,4]
b=[3,4,5,1,2]
print(list(set(a)& set(b)))

#source code --> clcoding.com 

Output:

[1, 2, 4, 5]

10. one liner FizzBuzz


print(['Fizz'*(i%3==0)+'Buzz'*(i%5==0) or i for i in range(1,16)])

#source code --> clcoding.com 

Output:

[1, 2, 'Fizz', 4, 'Buzz', 'Fizz', 7, 8, 'Fizz', 'Buzz', 11, 'Fizz', 13, 14, 'FizzBuzz']

7 Lesser-Known Pandas Functions That’ll Blow Your Mind


1. explode()=Turns list items into rows

import pandas as pd

df = pd.DataFrame({"Name": ["A", "B"], 
                   "Tags": [["x", "y"], ["p", "q"]]})
df.explode("Tags")

#source code --> clcoding.com
Output:
NameTags
0Ax
0Ay
1Bp
1Bq

2. query()- Filter rows using expression


df = pd.DataFrame({"Age":[20,25,30], "Score":[90,85,70]})
df.query("Age > 22 and Score > 80")

#source code --> clcoding.com

Output:

AgeScore
12585

3. nlargets()- Get the top n rows


df=pd.DataFrame({"Name":["A","B","C"],"Marks":[50,95,80]})
df.nlargest(1,"Marks")
#source code --> clcoding.com

Output:

NameMarks
1B95

4. nsmallest()- Get the lowest n rows


df=pd.DataFrame({"A":[10,3,7],"B":[4,9,1]})
df.nsmallest(2,"A")
#source code --> clcoding.com

Output:

AB
139
271



5. pivot_table()- Create summary table automatically


df=pd.DataFrame({
    "City":["A","A","B","B"],
    "Sales": [10,20,30,5]
})
df.pivot_table(values="Sales",index="City",aggfunc="sum")

#source code --> clcoding.com

Output:

Sales
City
A30
B35

6. fillna(method="ffill")- Fills missing values forward


df = pd.DataFrame({"X":[1,None,None,4]})
df.fillna(method="ffill")

#source code --> clcoding.com

Output:

X
01.0
11.0
21.0
34.0

7. assign()- Adds new column cleanly


df = pd.DataFrame({"A":[1,2,3]})
df = df.assign(B=df.A * 10)
print(df)

#source code --> clcoding.com

Output:

   A   B
0  1  10
1  2  20
2  3  30



Wednesday, 12 November 2025

Python Coding Challenge - Question with Answer (01131125)

 


Explanation:

Create a List
nums = [2, 4, 6]

A list named nums is created with three integer elements: 2, 4, and 6.

This will be used to calculate the average of its elements later.

Initialize Loop Control Variables
i = 0
s = 0

i → Acts as a loop counter, starting from 0.

s → A sum accumulator initialized to 0.
It will store the running total of the numbers in the list.

Start the While Loop
while i < len(nums):

The loop runs as long as i is less than the length of the list nums.

Since len(nums) is 3, this means the loop will run while i = 0, 1, 2.

This ensures every element in the list is processed once.

Add the Current Element to the Sum
    s += nums[i]

At each loop iteration:

The element at index i is accessed: nums[i].

It is added to the sum s.

Example of how s changes:

When i=0: s = 0 + 2 = 2

When i=1: s = 2 + 4 = 6

When i=2: s = 6 + 6 = 12

Increment the Loop Counter
    i += 1

After processing one element, i increases by 1.

This moves to the next element of the list in the next iteration.

Print the Final Result
print(s // len(nums))

Once the loop ends, the total sum s is 12.

The expression s // len(nums) performs integer division:

12 // 3 = 4

Hence, it prints the average (integer form) of the list elements.

Final Output

4

Probability and Statistics using Python


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