Python Coding challenge - Day 612| What is the output of the following Python Code?

 

Code Explanation:

1. Function Definition

def g():

    for i in range(3):

        yield i

This defines a generator function named g.

Inside, it has a for loop from i = 0 to 2 (because range(3)).

The yield keyword makes this a generator — it will return one value at a time and pause between them.

2. Create Generator Object

gen = g()

This line calls the generator function g() but does not run it immediately.

Instead, it creates a generator object and stores it in gen.

3. First Consumption

list(gen)

This line converts the generator gen to a list, consuming it completely.

The generator yields: 0, 1, 2, then it finishes.

So this returns [0, 1, 2], but the result is not printed or saved, so it is discarded.

4. Second Consumption

print(list(gen))

At this point, the generator gen has already been fully consumed in the previous list(gen) call.

Generators cannot be reused or reset unless explicitly recreated.

So now, list(gen) returns an empty list: [].

Final Output

[]

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