Python Coding Challange - Question with Answer (01080725)

 

Explanation

✅ a = (i for i in range(3))

This is a generator expression.
It creates a generator that will yield values one by one from range(3) → 0, 1, 2.

At this point, nothing is printed. The generator is lazy, meaning it does not compute values until requested.

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✅ print(next(a))

This calls next() on the generator a.
The first value yielded from the range is 0.

So it prints:

0

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✅ print(next(a))

Now, the generator moves to the next value, which is 1.

So it prints:

1

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✅ Final Output

0
1

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 Note:

If you call next(a) again, it would print 2. After that, another next(a) would raise a StopIteration error because there are no more items in the generator.

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