Monday, 7 July 2025

Python Coding Challange - Question with Answer (01180725)

 


Let's break down the code line by line to explain what's happening:


x = [0] * 3

✅ This creates a list with three zeroes:


x = [0, 0, 0]

x[0] = [1]

✅ You're replacing the first element (x[0]) with a list containing 1.
So now:

x = [[1], 0, 0]


x[1] = x[0]

✅ You're making x[1] refer to the same list object as x[0].
Both x[0] and x[1] now point to [1]:

x = [[1], [1], 0]

x[0][0] = 99

✅ This changes the first element inside the inner list at x[0] to 99.

But since x[1] is also pointing to the same list, the change reflects there too!

So now:


x = [[99], [99], 0]

✅ Final Output:


[[99], [99], 0]

 Key Concept:

This demonstrates aliasing or shared references — both x[0] and x[1] refer to the same list object in memory. Modifying one affects the other.

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