Python Coding challenge - Day 597| What is the output of the following Python Code?

 

Code Explanation:

1. Define the Generator Function

def g():

    yield 1

    yield 2

This is a generator function.

When called, it returns a generator object.

The first time next() is called, it yields 1.

The second time, it yields 2.

The third time, there is nothing left to yield, so it raises StopIteration.

2. Create Generator Object

x = g()

This creates a generator object x.

No code in the function runs yet.

3. First next(x)

print(next(x))

The generator starts and executes until the first yield.

Yields 1.

Prints:

1

4. Second next(x)

print(next(x))

Continues from where it left off.

Yields 2.

Prints:

2

5. Third next(x)

print(next(x))

The generator tries to continue but there are no more yield statements.

This causes a StopIteration error.

Since it's not caught, it crashes the program.

What Will Actually Happen

The output will be:

1

2

StopIteration

Final Output:

1 2 StopIteration

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