Sunday, 13 July 2025

Python Coding Challange - Question with Answer (01130725)

 


tep-by-Step Explanation:

  1. Variable Initialization:

    a = 10
    • You define a variable a with the value 10.

  2. Function Call:

    modify(a)
    • The function modify is called with a as the argument.

    • Inside the function, x = a, so x = 10.

  3. Inside the Function:

    x = x + 5
    • This creates a new local variable x inside the function.

    • It adds 5 to x, making x = 15, but this does NOT affect the original a outside the function.

  4. Printing a:

    print(a)
    • a still holds the original value 10, because integers are immutable in Python and reassignment inside the function doesn’t change the original variable.


Output:

10

Key Concept:

Python uses pass-by-object-reference, and integers are immutable. So when you modify a number inside a function, it does not affect the original variable.

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