Python Coding Challange - Question with Answer (01040725)

 

What's going on?

You're defining a variable x = 0 outside the function (global scope), and then trying to increment x inside the function.

---

What happens when you run this?

You'll get an error:

UnboundLocalError: local variable 'x' referenced before assignment

---

❓ Why?

Python thinks x inside the function is a local variable, because you're assigning to it with x += 1. However, you're also trying to read its value before the assignment — and since there's no local x defined yet, Python throws an error.

---

✅ How to fix it?

You can fix it by telling Python that x inside func() refers to the global x, using the global keyword:

x = 0
def func():
    global x
    x += 1
    print(x)
func()

🟢 Output:

1

Now x += 1 modifies the global variable x.

---

Key Concept:

When you assign to a variable inside a function, Python assumes it's local, unless you declare it as global or nonlocal.

100 Python Programs for Beginner with explanation 

https://pythonclcoding.gumroad.com/l/qijrws