Python Coding challenge - Day 652| What is the output of the following Python Code?

 

Code Explanation:

1. Function Definition

def make_adder(x):

    return lambda y: lambda z: x + y + z

Explanation:

This defines a function called make_adder that takes one argument x.

Inside the function, it returns a lambda function, which itself returns another lambda function.

So, it's a function that returns a function that returns a function.

Structure:

make_adder(x)

    └── lambda y:

           └── lambda z: x + y + z

Each time you call a lambda, it returns another function until all arguments x, y, and z are supplied.

2. First Function Call

f = make_adder(2)

Explanation:

You're calling make_adder(2), so now x = 2.

This returns a new function: lambda y: lambda z: 2 + y + z

The variable f now holds this function:

f = lambda y: lambda z: 2 + y + z

3. Second Function Call

g = f(3)

Explanation:

Now f is lambda y: lambda z: 2 + y + z

You're calling f(3), so y = 3

This evaluates to:

g = lambda z: 2 + 3 + z

So g is now a function that takes one argument z and returns 2 + 3 + z (which is 5 + z).

4. Final Function Call

print(g(4))

Explanation:

Now g = lambda z: 5 + z

Calling g(4) means z = 4, so:

g(4) = 5 + 4 = 9

So the output is:

9

Final Output

9

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