Python Coding challenge - Day 689| What is the output of the following Python Code?

 

Code Explanation:

1. Defining a Decorator

def dec(f):

    def wrap(x=2): return f(x) + 5

    return wrap

dec is a decorator factory.

It accepts a function f.

Inside it defines another function wrap:

wrap takes an argument x, defaulting to 2 if no value is passed.

It calls the original function f(x) and adds 5 to the result.

Finally, wrap is returned (replaces the original function).

2. Decorating a Function

@dec

def k(x): return x*3

Normally: def k(x): return x*3 defines a function.

Then @dec immediately wraps k with dec.

Effectively, after decoration:

k = dec(k)

So now, k is not the original function anymore. It is actually the wrap function returned by dec.

3. Calling the Decorated Function

print(k())

k() is actually calling wrap().

Since no argument is passed, wrap uses its default parameter x=2.

Inside wrap:

Calls the original k(2) (the old k before wrapping).

Original k(2) = 2*3 = 6.

Adds 5 → result = 11.

4. Output

11

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