Python Coding Challange - Question with Answer (01190825)

 

Great question 👍 Let’s go through the code step by step:

try:
   d = {"a": 1} # A dictionary with one key "a" and value 1
   print(d["b"]) # Trying to access key "b" which does not exist
except KeyError: 
    print("missing key")

 Explanation:

1. Dictionary Creation
   d = {"a": 1}
   → A dictionary is created with only one key-value pair:

   {"a": 1}

2. Accessing a Key
   print(d["b"])
   → Python looks for the key "b" in the dictionary.
   Since "b" does not exist, Python raises a KeyError.

3. Exception Handling
   The try block has an except KeyError clause.
   So instead of crashing, Python runs:

   print("missing key")

4. Output

   missing key

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✅ Final Output:

missing key

400 Days Python Coding Challenges with Explanation