Python Coding Challange - Question with Answer (01290825)

 

This is a tricky Python try/finally behavior. Let’s go step by step.

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Code:

def test():
    try:
       return 1
    finally:
           return 2
print(test())

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Step 1: Entering the try block

• Inside try, we hit:

  return 1

• So Python prepares to return 1.

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Step 2: But finally always runs

• Before leaving the function, Python always executes the finally block, no matter what.

• Here, the finally block has:

  return 2

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Step 3: Return value override

• The finally block overrides whatever was going to be returned from try.

• So the return 1 gets discarded, and the function actually returns 2.

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Final Output:

2

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✅ Explanation: In Python, finally always runs, and if it has a return, it overrides the return in try/except.

APPLICATION OF PYTHON FOR CYBERSECURITY