Thursday, 21 August 2025

Python Coding Challange - Question with Answer (01210825)

 


Let’s break this code step by step:

x = 5 y = (lambda z: z**2)(x)
print(y)

๐Ÿ”Ž Explanation:

  1. x = 5
    → Assigns integer 5 to variable x.

  2. (lambda z: z**2)
    → This is an anonymous function (created using lambda).
    It takes one argument z and returns z**2 (square of z).

    Equivalent to:

    def f(z): return z**2
  3. (lambda z: z**2)(x)
    → The lambda function is immediately called with the argument x (which is 5).
    → So it computes 5**2 = 25.

  4. y = (lambda z: z**2)(x)
    → The result 25 is stored in y.

  5. print(y)
    → Prints 25.


✅ Output:

25

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