Python Coding Challange - Question with Answer (01170825)

 

Let’s break this step by step 👇

def modify(z): 
    z = z ** 2 # inside the function, square z

• This defines a function modify that takes a parameter z.

• Inside the function, z = z ** 2 means: "take z and replace it with its square."

• But this assignment only changes the local copy of z inside the function.

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val = 4 # val is assigned 4
modify(val) # call the function with val as argument
print(val) # print val

• When calling modify(val), Python passes the value 4 into the function.

• Inside the function, z becomes 4, then z = 16.

• However, z is just a local variable inside modify.

• The original val outside the function remains unchanged because integers in Python are immutable.

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✅ Output:

4

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