Monday, 11 August 2025

Python Coding Challange - Question with Answer (01110825)

 


Let’s break this down step by step:



try:
d = {"a": 1} print(d["b"]) except KeyError: print("Key missing")

1️⃣ try:

  • This starts a try block — Python will run the code inside it, but if an error occurs, it will jump to the matching except block.


2️⃣ d = {"a": 1}

  • Creates a dictionary d with one key-value pair:

    • Key: "a"

    • Value: 1

So d looks like:


{"a": 1}

3️⃣ print(d["b"])

  • This tries to access the value for the key "b".

  • Since "b" is not present in the dictionary, Python raises a KeyError.


4️⃣ except KeyError:

  • This block catches errors of type KeyError.

  • Because the error matches, Python runs the code inside this block instead of stopping the program.


5️⃣ print("Key missing")

  • Prints the message "Key missing" to tell the user that the requested key doesn’t exist.


Final Output:

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