Python Coding Challenge - Question with Answer (ID -080226)

 

Code Explanation:

Initialize the number

n = 7; s = 0

n stores the limit (up to 7)

s is used to store the sum

Initially, sum is set to 0

Start the loop

for i in range(1, n+1, 2):

Loop starts from 1

Ends at n (7)

Step value 2 means only odd numbers are selected

(1, 3, 5, 7)

 Add odd numbers

s += i

Each odd number is added to s

Equivalent to s = s + i

Print the result

print(s)

Displays the final sum of odd numbers

✅ Final Output

16