Python Coding challenge - Day 1026| What is the output of the following Python Code?

 

Code Explanation:

1. Defining the Descriptor Class

class D:

A class named D is defined.

This class is going to be used as a descriptor.

2. Defining the __get__ Method

    def __get__(self, obj, owner):

        return 50

__get__ makes this class a descriptor.

This method is called whenever the attribute is accessed.

Parameters:

self → descriptor object (D instance)

obj → instance accessing the attribute (a)

owner → class owning the descriptor (A)

It always returns 50, no matter what.

3. Defining Class A

class A:

A class named A is defined.

4. Attaching the Descriptor to Class A

    x = D()

x is a class attribute.

Its value is an instance of D, so x becomes a descriptor-managed attribute.

5. Creating an Object of Class A

a = A()

An instance a of class A is created.

6. Assigning a Value to a.x

a.x = 10

Python tries to assign 10 to x.

Since the descriptor D does NOT define __set__, this assignment:

Creates an instance attribute:

a.__dict__['x'] = 10

7. Accessing a.x

print(a.x)

Step-by-step attribute lookup:

Python sees that x is a descriptor on class A

Descriptor takes priority over instance attributes

Python calls:

D.__get__(a, A)

__get__ returns 50

The instance value 10 is ignored

8. Final Output

50

✅ Final Answer

✔ Output:

50

900 Days Python Coding Challenges with Explanation