Python Coding Challange - Question with Answer (01120625)

 

Code Breakdown

• for i in range(3)
  → Outer loop: i takes values 0, 1, 2.

• for j in range(3)
  → Inner loop: for each i, j starts from 0 to 2.

• if j == 1: break
  → The inner loop breaks immediately when j equals 1.

• print(f"{i}-{j}")
  → Only runs when j is 0, because the loop breaks before j becomes 1.

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 Execution Flow

 First outer loop (i = 0)

• j = 0 → Not equal to 1 → prints 0-0

• j = 1 → Equals 1 → inner loop breaks

 Second outer loop (i = 1)

• j = 0 → prints 1-0

• j = 1 → breaks

Third outer loop (i = 2)

• j = 0 → prints 2-0

• j = 1 → breaks

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✅ Output:

0-0
1-0
2-0

Each time the inner loop only prints j=0, then hits j==1 and breaks.

 Python for Aerospace & Satellite Data Processing

https://pythonclcoding.gumroad.com/l/msmuee