Python Coding challenge - Day 579| What is the output of the following Python Code?

 

Code Explanation:

1. Function Definition

def func(a, L=[]):

A function named func is defined.

It takes two parameters:

a: a number (likely an integer).

L: a list with a default value of an empty list [].

2. Loop to Append Values

    for i in range(a):

        L.append(i)

A for loop runs from i = 0 to i = a - 1.

Each i is appended to the list L.

3. Return the List

    return L

After the loop, the modified list L is returned.

4. First Function Call

print(func(2))

a = 2, default L = [] (the empty list defined once at function creation).

Loop: i = 0, 1 → L becomes [0, 1]

Output: [0, 1]

5. Second Function Call

print(func(3))

a = 3, but now the default list L is not empty—it's [0, 1] from the previous call.

Loop: i = 0, 1, 2 → Append to existing list → L becomes [0, 1, 0, 1, 2]

Output: [0, 1, 0, 1, 2]

Final Output

[0, 1]

[0, 1, 0, 1, 2]

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