Monday, 9 June 2025

Python Coding Challange - Question with Answer (01100625)

 


What's happening here?

  1. Global Scope:
    Variable x = 10 is defined outside the function, so it's in the global scope.

  2. Inside func():

    print(x)
    x = 5

    Here, you're trying to print x before assigning x = 5.

    In Python, any assignment to a variable inside a function makes it a local variable, unless it's explicitly declared global or nonlocal.

    So Python treats x as a local variable in func() throughout the function body, even before the line x = 5 is executed.

  3. Error:
    When print(x) runs, Python is trying to access the local variable x before it has been assigned. This leads to:

    ❌ UnboundLocalError: cannot access local variable 'x' where it is not associated with a value


Fix it

If you want to access the global x, you can do:


def func():
global x print(x) x = 5 x = 10
func()

Or simply remove the assignment if not needed.


 Key Concept

If a variable is assigned anywhere in the function, Python treats it as local throughout that function—unless declared with global or nonlocal.

BIOMEDICAL DATA ANALYSIS WITH PYTHON 

https://pythonclcoding.gumroad.com/l/tdmnq

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