Saturday, 21 June 2025

Python Coding Challange - Question with Answer (01210625)

 


Step-by-Step Execution:

  1. Function Definition

    def gen():
    yield 10
    • This defines a generator function.

    • The keyword yield makes gen() return a generator object, not a regular value.

  2. Create Generator


    g = gen()
    • Now, g is a generator object that will produce values when next(g) is called.

  3. First next(g)

    next(g)
    • This starts the generator.

    • It runs the function up to the first yield, which is:

      yield 10
    • So it yields 10, and pauses.

  4. Second next(g)


    next(g)
    • The generator resumes after the yield.

    • But there's nothing left in the function.

    • So it raises a StopIteration exception.


 What Happens When You Run It?

  • First next(g) → works, returns 10.

  • Second next(g) → raises:

    StopIteration

✅ Visual Summary:


def gen():
yield 10 ← (1st call yields 10) ↑ paused here -- 2nd next(g) resumes here
-- But function is over ⇒ StopIteration

✅ Final Advice:

If you want to handle it safely:


g = gen()
print(next(g)) try: print(next(g)) except StopIteration:
print("Generator exhausted")

Python for Ethical Hacking Tools, Libraries, and Real-World Applications

https://pythonclcoding.gumroad.com/l/bjncjn

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