Python Coding challenge - Day 473| What is the output of the following Python Code?

 

Code Explanation:

Importing defaultdict:

defaultdict(int) creates a dictionary where the default value for any key that doesn't exist is 0 (since int() gives 0).

The String "banana":

The string "banana" consists of the following characters: b, a, n, a, n, a.

Looping through "banana":

The loop iterates through each character in the string "banana" and increments its corresponding count in the freq dictionary.

Here’s how the dictionary evolves during the loop:

For the first character b, the default value is 0, so freq['b'] becomes 1.

For the second character a, the default value is 0, so freq['a'] becomes 1.

For the third character n, the default value is 0, so freq['n'] becomes 1.

For the fourth character a, freq['a'] is already 1, so it's incremented to 2.

For the fifth character n, freq['n'] is already 1, so it's incremented to 2.

For the sixth character a, freq['a'] is already 2, so it's incremented to 3.

Printing freq['a'] and freq['n']:

After the loop, the frequency count of the characters is:

'a' appears 3 times

'n' appears 2 times

So, freq['a'] = 3 and freq['n'] = 2.

Output:

3 2