Saturday, 31 May 2025

Python Coding Challange - Question with Answer (01310525)

 


Line-by-Line Explanation:

๐Ÿ”ธ n = 2

  • Initializes a variable n with value 2.


๐Ÿ”ธ while n < 20:

  • This starts a loop that runs as long as n is less than 20.


๐Ÿ”ธ print(n)

  • Prints the current value of n.


๐Ÿ”ธ n *= 2

  • Multiplies n by 2.
    (Same as n = n * 2)


๐Ÿ”ธ if n > 15: break

  • If n becomes greater than 15, the loop is stopped immediately with break.


 Step-by-Step Execution:

StepValue of nPrinted?After n *= 2n > 15?Break?
12✅ 24❌ NoNo
24✅ 48❌ NoNo
38✅ 816✅ Yes✅ Break
 Final Output:
2
4
8

 Summary:

  • This is a while loop with:

    • A multiplication step (n *= 2)

    • A condition to stop early (break if n > 15)

  • The loop prints 2, 4, 8, then exits when n becomes 16


APPLICATION OF PYTHON FOR CYBERSECURITY 

https://pythonclcoding.gumroad.com/l/dfunwe

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