Python Coding Challange - Question with Answer (01210525)

 

Step-by-step Explanation:

1. Function Definition:

   
   def foo():
       return "Original"

   This defines a normal function foo that returns the string "Original". At this point, foo refers to this function.

2. Function Overwriting:

   foo = lambda: "Reassigned"

   Now you're overwriting the foo identifier. Instead of pointing to the function defined earlier, it now points to a lambda function (an anonymous function) that returns "Reassigned".

   ✅ The original foo() function is still in memory, but it's now inaccessible because the name foo now refers to something else.

3. Function Call:

   
   print(foo())

   Now when you call foo(), you're calling the lambda function, which returns "Reassigned". So the output will be:

   
   Reassigned

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Key Concept:

In Python, functions are objects, and variable names (like foo) can be reassigned just like any other variable. Once you assign a new function (or any value) to foo, the original one is no longer accessible through that name.

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