Python Coding challenge - Day 492| What is the output of the following Python Code?

 

Code Explanation:

1. funcs = []

What happens:

Creates an empty list named funcs that will later store lambda functions.

2. for i in range(3):

What happens:

Starts a loop where i takes values 0, 1, and 2 in sequence.

3. funcs.append(lambda i=i: i*i)

Key point: The lambda function is defined with a default argument i=i.

Why use i=i?

This binds the current value of i at each loop iteration to the lambda’s parameter i. It effectively “freezes” the value of i for that lambda.

What does the lambda do?

It returns i*i, the square of its argument i.

Effect:

Three lambda functions are created and appended to funcs:

First lambda has default i=0 → returns 0*0 = 0

Second lambda has default i=1 → returns 1*1 = 1

Third lambda has default i=2 → returns 2*2 = 4

4. for f in funcs:

What happens:

Iterates over each lambda function stored in funcs.

5. print(f())

What happens:

Calls each lambda function without any argument.

Because of default argument:

The lambda uses its default value of i captured during creation.

Output:

Prints the square of the captured i for each lambda:

0

1

4