Code Explanation:
Function: reduce_to_one(n)
This function implements a process related to the Collatz conjecture — it reduces a number n down to 1 by following these rules recursively, and it counts the number of steps taken.
1. Base Case: Check if n is already 1
if n == 1:
return 0
What it does:
If the input number n is already 1, the function returns 0 because no more steps are needed to reduce it further.
This is the stopping condition for the recursion.
2. If n is Even
if n % 2 == 0:
return 1 + reduce_to_one(n // 2)
What it does:
If n is even (i.e., divisible by 2), it divides n by 2 and makes a recursive call on this smaller number.
It adds 1 to count this step (the division by 2).
The function keeps going until it reaches 1.
3. If n is Odd
else:
return 1 + reduce_to_one(3 * n + 1)
What it does:
If n is odd, it applies the formula 3 * n + 1 and recursively calls itself with this new value.
Again, adds 1 to count this step.
4. Example Call and Output
print(reduce_to_one(3))
How it works step-by-step for n = 3:
Step Current n Action Next n Steps so far
1 3 (odd) 3 * 3 + 1 = 10 10 1
2 10 (even) 10 // 2 = 5 5 2
3 5 (odd) 3 * 5 + 1 = 16 16 3
4 16 (even) 16 // 2 = 8 8 4
5 8 (even) 8 // 2 = 4 4 5
6 4 (even) 4 // 2 = 2 2 6
7 2 (even) 2 // 2 = 1 1 7
8 1 Stop - 0 (base case)
Total steps taken: 7
The function returns 7.
Output:
7
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