Code Explanation:
Function Definition with a Mutable Default Argument
def f(key, val, d={}):
d[key] = val
return d
A function f is defined with three parameters: key, val, and d (defaulting to an empty dictionary {}).
Important: In Python, default values are evaluated only once, at the time the function is defined, not each time it's called.
So d={} creates one shared dictionary used across calls that don't provide a new one.
First Call: f('a', 1)
f('a', 1)
key='a', val=1, d uses the default value {}.
Adds 'a': 1 to d, so now:
d = {'a': 1}
Second Call: f('b', 2)
f('b', 2)
key='b', val=2, again uses the same default dictionary d.
Adds 'b': 2, so now:
d = {'a': 1, 'b': 2}
Third Call and Final Output
print(f('c', 3)['a'])
key='c', val=3, again uses the same shared dictionary.
Adds 'c': 3, so now:
d = {'a': 1, 'b': 2, 'c': 3}
Then f('c', 3)['a'] retrieves the value of key 'a' → 1
Final Output
1
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