Python Coding Challenge - Question with Answer (ID -170626)

 

Explanation:

🔹 Line 1: Call zip()

zip([1,2], [3], strict=True)

We are passing:

[1,2]

and

[3]

to zip().

Length of first list:

2

Length of second list:

1

🔹 Step 2: Understand Normal zip()

Without strict=True:

list(zip([1,2], [3]))

Output:

[(1, 3)]

Why?

Because normal zip() stops when the shortest iterable ends.

Visual:

[1,2]

[3]

Pair created:

(1,3)

Now second list is exhausted.

So zip() stops.

🔹 Step 3: What Does strict=True Do?

zip(..., strict=True)

was introduced in Python 3.10.

It means:

All iterables must have exactly the same length.

If lengths differ:

Raise ValueError

instead of silently stopping.

🔹 Step 4: First Pair Creation

Python creates:

(1,3)

No problem yet.

Current result:

[(1,3)]

🔹 Step 5: Check for More Elements

Python tries to get next values.

First list still has:

2

remaining.

Second list has:

nothing

remaining.

Visual:

List 1 → [2]

List 2 → []

Lengths no longer match.

🔹 Step 6: strict=True Detects Mismatch

Python sees:

First iterable still has items

but

Second iterable is exhausted

This violates:

strict=True

So Python raises:

ValueError

🔹 Step 7: list() Never Completes

list(zip(...))

cannot finish.

Execution stops immediately with:

Final Output

ValueError

Book: Python for Cybersecurity