Python Coding challenge - Day 1170| What is the output of the following Python Code?

 

Code Explanation:

🔹 1. Creating an Empty List

funcs = []

✅ Explanation:

An empty list named funcs is created.

This list will store lambda functions.

Current state:

[]

🔹 2. Starting the Loop

for i in range(3):

✅ Explanation:

range(3) generates:

0, 1, 2

The loop runs 3 times.

🔹 3. First Iteration (i = 0)

funcs.append(lambda: i)

✅ Explanation:

A lambda function is created:

lambda: i

and stored in the list.

Current List

[

    lambda: i

]

⚠️ Important:

The lambda does not store the value 0.

It stores a reference to variable i.

🔹 4. Second Iteration (i = 1)

Again:

funcs.append(lambda: i)

Current list:

[

    lambda: i,

    lambda: i

]

Again, both lambdas refer to the same variable i.

🔹 5. Third Iteration (i = 2)

Again:

funcs.append(lambda: i)

Current list:

[

    lambda: i,

    lambda: i,

    lambda: i

]

🔹 6. Loop Ends

After the loop finishes:

i = 2

⚠️ Very Important

There is only one variable i.

All lambdas point to this same variable.

Final value:

2

🔹 7. First Function Call

print(funcs[0]())

What happens?

Python executes:

lambda: i

Current value of i:

2

So result:

2

Printed:

2

🔹 8. Second Function Call

print(funcs[2]())

What happens?

Third lambda is also:

lambda: i

Current value of i is still:

2

Result:

2

Printed:

2

🎯 Final Output

2

2