Python Coding Challenge - Question with Answer (ID -050626)

 

Explanation:

🔹 Step 1: Create Empty List

x = []

An empty list is created:

[]

Memory:

x ──► []

🔹 Step 2: Append the List to Itself

x.append(x)

Normally we do:

x.append(1)

or

x.append("A")

But here we're doing:

x.append(x)

which means:

Append the list itself inside itself

After execution:

x = [x]

Visual representation:

x

│

▼

[ x ]

More accurately:

x

│

▼

The list contains a reference to itself.

🔹 Step 3: Understand x[0]

x[0]

First element of the list is:

x

itself.

So:

x[0] is x

becomes:

True

Both point to the exact same object.

🔹 Step 4: Evaluate Comparison

x == x[0]

Substitute:

x == x

Python is effectively comparing the same object with itself.

Result:

True

🔹 Step 5: Print Result

print(True)

Output:

True