🚀 Day 60/150 – Find Second Largest Element in Python

 

🚀 Day 60/150 – Find Second Largest Element in Python

The second largest element is the number that is just smaller than the largest number in the list.

Example:
[10, 20, 4, 45, 99] → Largest = 99, Second Largest = 45

Let’s explore different ways to find it 👇

🔹 Method 1 – Using Sorting

numbers = [10, 20, 4, 45, 99]

numbers.sort()

print("Second Largest:", numbers[-2])

🔹 Method 2 – Using set() + max()

numbers = [10, 20, 4, 45, 99] numbers = list(set(numbers)) numbers.remove(max(numbers)) print("Second Largest:", max(numbers))

🔹 Method 3 – Using Loop

numbers = [10, 20, 4, 45, 99] largest = second = float('-inf') for num in numbers: if num > largest: second = largest largest = num elif num > second and num != largest: second = num print("Second Largest:", second)

🔹 Method 4 – Taking User Input

numbers = list(map(int, input("Enter numbers: ").split())) numbers = sorted(set(numbers)) print("Second Largest:", numbers[-2])

💡 Key Takeaways

• Sorting is the easiest way
• set() helps remove duplicates
• Loop method is efficient because it scans only once
• Always consider duplicate values when finding the second largest