Python Coding Challange - Question with Answer (01120925)

 

Step-by-step execution:

• Initial value: i = 0

Iteration 1:

• Condition: i < 5 → 0 < 5 ✅

• i += 1 → i = 1

• if i == 3 → 1 == 3 ❌

• print(i) → prints 1

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Iteration 2:

• Condition: i < 5 → 1 < 5 ✅

• i += 1 → i = 2

• if i == 3 → 2 == 3 ❌

• print(i) → prints 2

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Iteration 3:

• Condition: i < 5 → 2 < 5 ✅

• i += 1 → i = 3

• if i == 3 → 3 == 3 ✅ → continue triggers

  • continue means: skip the rest of this loop (so print(i) is not executed).

• Nothing printed.

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Iteration 4:

• Condition: i < 5 → 3 < 5 ✅

• i += 1 → i = 4

• if i == 3 → 4 == 3 ❌

• print(i) → prints 4

---

Iteration 5:

• Condition: i < 5 → 4 < 5 ✅

• i += 1 → i = 5

• if i == 3 → 5 == 3 ❌

• print(i) → prints 5

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✅ Final Output:

1 2 4 5

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👉 The key point: continue skips printing when i == 3, but the loop keeps running.

500 Days Python Coding Challenges with Explanation