Code Explanation:
1. Importing the heapq Module
import heapq
The heapq module provides functions to work with heaps (a type of priority queue).
By default, Python’s heapq implements a min-heap → the smallest element is always at the root (index 0).
2. Creating the List
nums = [6, 2, 9, 1]
A normal Python list is created with numbers [6, 2, 9, 1].
Currently, it’s just a list, not a heap yet.
3. Converting the List into a Heap
heapq.heapify(nums)
This rearranges the list into min-heap order in-place.
After heapify, the smallest element becomes the first element (index 0).
Resulting heap (internally): [1, 2, 9, 6].
Here, 1 is the root, 2 is next, etc. (heap property is satisfied).
4. Pushing a New Element into the Heap
heapq.heappush(nums, 0)
Adds the value 0 to the heap.
Heap automatically rearranges to maintain the min-heap property.
Heap now becomes: [0, 1, 9, 6, 2].
5. Removing and Returning the Smallest Element
heapq.heappop(nums)
Removes and returns the smallest element (root) from the heap.
Smallest = 0.
Heap after removal adjusts to maintain order: [1, 2, 9, 6].
6. Getting the Two Largest Elements
heapq.nlargest(2, nums)
Finds the 2 largest elements from the heap/list.
Current heap: [1, 2, 9, 6].
Largest two = [9, 6].
7. Printing the Results
print(heapq.heappop(nums), heapq.nlargest(2, nums))
First, it pops the smallest element (1).
Then finds the 2 largest elements ([9, 6]).
Final Output:
1 [9, 6]
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