Saturday, 20 September 2025

Python Coding Challange - Question with Answer (01210925)

 


Sure ๐Ÿ‘ Let’s carefully break this code down step by step:


๐Ÿงฉ Code:

a = [i**2 for i in range(6) if i % 2]
print(a)

๐Ÿ”น Step 1: Understanding range(6)

range(6) generates numbers from 0 to 5:

[0, 1, 2, 3, 4, 5]

๐Ÿ”น Step 2: Condition ifi % 2

  • i % 2 means remainder when i is divided by 2.

  • If the remainder is not 0, it’s an odd number.

  • So only odd numbers are kept:

[1, 3, 5]

๐Ÿ”น Step 3: Expression i**2

  • For each remaining number, calculate its square (i**2).

  • 1**2 = 1 
    3**2 = 9 
    5**2 = 25

๐Ÿ”น Step 4: Final List

So, the list comprehension produces:

a = [1, 9, 25]

๐Ÿ”น Step 5: Printing

print(a) outputs:

[1, 9, 25]

✅ This is a list comprehension that filters odd numbers from 0–5 and squares them.

PYTHON FOR MEDICAL SCIENCE

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