Code Explanation:
1. Importing heapq
import heapq
We import the heapq module, which allows us to work with min-heaps in Python.
2. Creating a List
nums = [8, 3, 6]
A normal Python list is created.
Currently: nums = [8, 3, 6].
3. Converting List to Heap
heapq.heapify(nums)
This function rearranges the list into a min-heap structure.
After heapify: nums = [3, 8, 6] (smallest element always at index 0).
4. Adding a New Element
heapq.heappush(nums, 2)
Adds the value 2 to the heap while keeping heap properties.
Heap after push: nums = [2, 3, 6, 8].
5. Removing the Smallest Element
x = heapq.heappop(nums)
Removes and returns the smallest element (root of the heap).
Here, x = 2.
Heap becomes: nums = [3, 8, 6].
6. Printing the Result
print(x, heapq.nlargest(2, nums))
x = 2.
heapq.nlargest(2, nums) → finds the two largest elements in [3, 8, 6], which are [8, 6].
Final Output
2 [8, 6]
.png)

0 Comments:
Post a Comment